How Do I Reduce 5v To 1.5 V?

How do I reduce 5v to 3.7 V?

To convert 5 v to 3.7 v at fixed load ,we just have to add a fixed series resistor.

5 to 3.7 that means our series resistor have to create 1.3 v drop across it.

For load 0.5A , R= 2.6Ohms and power rating is 0.65W.

Idea of using zener diode is good with small series resistor..

How do I reduce 12v to 5v?

Convert 12V DC to 5V DCStep 1: Take All Components As Shown Below and in Pictures. Components required – … Step 2: Connect Input Power Supply. 7805 voltage regulator contain three pins.In which we have to give power supply on pin-1 and pin-2. … Step 3: Output Power Supply. … Step 4: Wiring Is Completed. … Step 5: Checking.

How do I reduce 5v to 4.5 V?

Just put a silicon diode (e.g. 1N4001) in series with the laser supply, it will drop a fairly consistant 0.7v. Use two, if you want to be on the safe side. Just put a silicon diode (e.g. 1N4001) in series with the laser supply, it will drop a fairly consistant 0.7v. Use two, if you want to be on the safe side.

How do you convert 5v dc to 1.5 V DC?

In voltage divider circuit you want to drop 3.8V across R1 to get Vout = 1.5V. This can be done by n number of combinations of R1 & R2 values. For e.g. you can use R1=3.8K and R2=1.2K or R1=3.8Ω and R2= 1.2Ω.

Can I use a 5v charger with a 3.7 V battery?

The 5v ‘charger’ is actually just a 5v DC power source. … A battery needs a higher voltage power source than the current battery voltage in order to recharge. To fully recharge a lithium ion cell, you need to eventually get to 4.2v. If the system only used 3.7v, it would never (fully) recharge.

How do you reduce 9 volts to 3 volts?

To reduce a 9V battery to 3.3 volts, use a zener diode, such as a 1N746 or a 1N4728A. Choose the appropriate one based on how much power it can dissipate. A 1N4728A has a 3.3-volt and a 1 W power rating. It can supply, on average, a stable 3.3 volts to a circuit or another component.

What voltage should I charge my 3.7 V battery?

Lithium-ionNominal cell voltageTypical end-of-dischargeMax charge voltage3.6V2.8–3.0V4.2V3.7V2.8–3.0V4.2V3.8V2.8–3.0V4.35V3.85V2.8–3.0V4.4VMay 9, 2017

How do capacitors reduce voltage?

The conventional method is the use of a step-down transformer to reduce the 230 V AC to a desired level of low voltage AC. The most simple, space saving and low cost method is the use of a Voltage Dropping Capacitor in series with the phase line.

How do I reduce 220v to 12v?

A step-down transformer would help you reduce your 220V AC to a more manageable 20V or 30V AC. Then you can use a rectifier to convert this AC to DC. Finally, use a voltage regulator such as the LM7812 to convert 20V DC to 12V DC.

How do I reduce 5v to 4v?

From 5v to 4v (ish) all you need is a simple and cheap silicon diode. You will drop about 0.7v over a diode which is probably near enough? Just make sure the diode is rated for the power you need.

Can I use a 5v 2a charger with a 5v 1a device?

The 2A port is capable of passing twice as many electrons per second. The current draw (Amperes) is controlled by the device you plug in. So if you plug a 1A device into a 2A charger, it will still only draw 1A.

Can I use 4.5 V instead of 5v?

Another thing to note: Most digital devices today that run off 5V feed that rail directly into a voltage regulator which drops it to 3.3V or lower. Those devices need the input voltage to be a little higher than the target voltage, so maybe 3.6-3.9V at a minimum. Bottom line, you should be fine with the 4.5V supply.

How do I reduce 9v to 5v?

This is the circuit used to convert 9V to 5V in such cases. IC7805 is a series voltage regulator IC which gives you a fixed voltage of 5V at output with maximum of 1A current in TO-220 package (commonly given) and upto 2A in TO-3 package with adequate heat-sinks!

How do I convert 7805 to 12v to 5v?

12V battery to 5V 1.5A DC converter I use the 7805 power supply with the 12V battery. To reduce the constant voltage of 5 volts. Testing pure IC-7805 not over 1A current. It requires a transistor to increase the output current up.

How can you reduce voltage without reducing current?

Voltage dividers are used for really low current situations. Either use a linear regulator, such as the LM317, which will reduce the voltage by burning it off as heat. Or if efficiency is important, you can buy a cheap adjustable DC-DC switchmode regulator for like $3 on ebay.

How can I reduce 10v to 5v?

To divide voltage in half, all you must do is place any 2 resistors of equal value in series and then place a jumper wire in between the resistors. At this point where the jumper wire is placed, the voltage will be one-half the value of the voltage supplying the circuit. The 5V is now 2.5V.

How do you reduce voltage drop?

The simplest way to reduce voltage drop is to increase the diameter of the conductor between the source and the load, which lowers the overall resistance. In power distribution systems, a given amount of power can be transmitted with less voltage drop if a higher voltage is used.

How do you reduce 12 volts to 9 volts?

Step Down the Voltage Install the smaller resistor first, stepping down your voltage from 12V to 11V. Once you’ve added the first resistor to your circuit, install the larger resistor to step the voltage down again. This resistor will take the remaining 11V current and reduce it to the 9V output you desire.

Can you charge something with a higher voltage?

Voltage too high – If the adapter has a higher voltage, but the current is the same, then the device will likely shut itself off when it detects an overvoltage. If it doesn’t, then it may run hotter than normal, which can shorten the life of the device or cause immediate damage.

How do you reduce a 12v to 5v with a resistor?

Connect 12 v to pin 1 ,pin 2 is the ground and pin3 gives 5v. Don’t want to use IC or not getting it,use a voltage divider using 2 resistors and you are done with it. Connect 12 v across the series combination of 4.7k ohm and 6.8k ohm(readily available standard ) resistor and take the output across 4.7k ohm.

Can I use 12v for 5v?

Current is decided by Ohms law, I=V/R. With 12V your device will draw double the current and gets heated up because all current limiting values of your device are calculated for 5V source. … Most TTL ICs which are rated for 5V have a max acceptable voltage limit at 7V. Same is true for 5V microcontrollers.